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2t^2-7t-22=0
a = 2; b = -7; c = -22;
Δ = b2-4ac
Δ = -72-4·2·(-22)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-15}{2*2}=\frac{-8}{4} =-2 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+15}{2*2}=\frac{22}{4} =5+1/2 $
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